What is the projected image width of a part 6 inches wide at an SID of 44 inches and 9 inches from the IR?

Prepare for the Image Acquisition and Technical Evaluation Test with comprehensive quizzes, flashcards, and multiple-choice questions. Access detailed explanations and study tips to excel in your exam!

Multiple Choice

What is the projected image width of a part 6 inches wide at an SID of 44 inches and 9 inches from the IR?

Explanation:
To determine the projected image width of a part that is 6 inches wide at a Source to Image Distance (SID) of 44 inches and an object distance of 9 inches from the image receptor (IR), you can apply the concept of magnification. Magnification in radiography is calculated using the formula: \[ \text{Magnification} = \frac{\text{SID}}{\text{SOD}} \] where SOD (Source to Object Distance) is the distance from the X-ray source to the object. The SOD can be calculated as: \[ \text{SOD} = \text{SID} - \text{Object Distance} \] In this case: - SID = 44 inches - Object Distance = 9 inches - Therefore, SOD = 44 inches - 9 inches = 35 inches. Now calculating the magnification: \[ \text{Magnification} = \frac{44 \text{ inches}}{35 \text{ inches}} \approx 1.257 \] Now to find the projected image width, you multiply the original object width by the magnification factor: \[ \text{Projected Image Width} = \text{Object Width} \times \

To determine the projected image width of a part that is 6 inches wide at a Source to Image Distance (SID) of 44 inches and an object distance of 9 inches from the image receptor (IR), you can apply the concept of magnification.

Magnification in radiography is calculated using the formula:

[ \text{Magnification} = \frac{\text{SID}}{\text{SOD}} ]

where SOD (Source to Object Distance) is the distance from the X-ray source to the object. The SOD can be calculated as:

[ \text{SOD} = \text{SID} - \text{Object Distance} ]

In this case:

  • SID = 44 inches

  • Object Distance = 9 inches

  • Therefore, SOD = 44 inches - 9 inches = 35 inches.

Now calculating the magnification:

[ \text{Magnification} = \frac{44 \text{ inches}}{35 \text{ inches}} \approx 1.257 ]

Now to find the projected image width, you multiply the original object width by the magnification factor:

[ \text{Projected Image Width} = \text{Object Width} \times \

Subscribe

Get the latest from Examzify

You can unsubscribe at any time. Read our privacy policy