To produce 18 mAs at 300 mA, what exposure time should be selected?

To produce 18 mAs at 300 mA, what exposure time should be selected?

• A. 40 ms
• B. 60 ms
• C. 400 ms
• D. 600 ms

Answer: (B)

To determine the exposure time needed to produce 18 mAs (milliampere-seconds) at a current of 300 mA (milliamperes), you can use the formula for calculating mAs: \[ \text{mAs} = \text{mA} \times \text{time (s)} \] Rearranging the formula to solve for time yields: \[ \text{time (s)} = \frac{\text{mAs}}{\text{mA}} \] Substituting the given values: \[ \text{time (s)} = \frac{18 \, \text{mAs}}{300 \, \text{mA}} \] Calculating this gives: \[ \text{time (s)} = \frac{18}{300} = 0.06 \, \text{s} \] To convert this to milliseconds, remember that 1 second equals 1000 milliseconds: \[ 0.06 \, \text{s} = 60 \, \text{ms} \] Thus, the correct exposure time to produce 18 mAs at 300 mA is 60 ms. This aligns with the choice given, making it

To determine the exposure time needed to produce 18 mAs (milliampere-seconds) at a current of 300 mA (milliamperes), you can use the formula for calculating mAs:

[ \text{mAs} = \text{mA} \times \text{time (s)} ]

Rearranging the formula to solve for time yields:

[ \text{time (s)} = \frac{\text{mAs}}{\text{mA}} ]

Substituting the given values:

[ \text{time (s)} = \frac{18 , \text{mAs}}{300 , \text{mA}} ]

Calculating this gives:

[ \text{time (s)} = \frac{18}{300} = 0.06 , \text{s} ]

To convert this to milliseconds, remember that 1 second equals 1000 milliseconds:

[ 0.06 , \text{s} = 60 , \text{ms} ]

Thus, the correct exposure time to produce 18 mAs at 300 mA is 60 ms. This aligns with the choice given, making it